#include<iostream>
using namespace std;
char a[10][10];
int n,x[10],nrsol,k;
int afisare()
{int i;
nrsol++;
for(i=1;i<=k;i++)
cout<<a[x[i]]<<" ";
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(x[j]==x[i] || x[i]==x[i-1] && i>1)
return 0;
return 1;
}
void back(int i)
{int j;
for(j=1;j<=n;j++)
{x[i]=j;
if(verif(i))
if(i==k)
afisare();
else back(i+1);
}
}
int main()
{int i;
cout<<"n=";cin>>n;
k=3;
for(i=1;i<=n;i++)
cin>>a[i];
back(1);
cout<<endl<<"Nr. sol= "<<nrsol;
}
sâmbătă, 3 noiembrie 2012
Problema 44
Se citesc n culori. Sa se formeze toate drapelele de 3 culori astfel incat oricare doua culori alaturate sa fie distincte.
Problema 61
Să se genereze toate codurile de lungime n morse formate din '.' şi '-' astfel încât să nu existe două puncte alăturate.
#include<iostream>
using namespace std;
char x[100];
int n,nr=0;
int verif(int i)
{if(i>1 && x[i]=='.' && x[i-1]=='.')
return 0;
else return 1;
}
void back(int i)
{char j;
for(j='-';j<='.';j=j+'.'-'-')
{x[i]=j;
if(verif(i))
if(i==n)
{ cout<<x+1<<endl;nr++;}
else back(i+1);
}
}
int main()
{cin>>n;
x[n+1]=NULL;
back(1);
cout<<endl<<nr<<" solutii";
}
#include<iostream>
using namespace std;
char x[100];
int n,nr=0;
int verif(int i)
{if(i>1 && x[i]=='.' && x[i-1]=='.')
return 0;
else return 1;
}
void back(int i)
{char j;
for(j='-';j<='.';j=j+'.'-'-')
{x[i]=j;
if(verif(i))
if(i==n)
{ cout<<x+1<<endl;nr++;}
else back(i+1);
}
}
int main()
{cin>>n;
x[n+1]=NULL;
back(1);
cout<<endl<<nr<<" solutii";
}
Problema 54 (nu e rezolvata in clasa)
La un concurs se prezinta n concurenti din m tari. Sa se stabileasca ordinea intrarii in concurs a celor n concurenti astfel incat doi concurenti din aceeasi tara sa nu urmeze unul dupa altul.
#include<iostream>
using namespace std;
int n,x[10],nr=0;
struct concurent{
int nr;
char tara[100];
}a[100];
int afisare(int n)
{for(int i=1;i<=n;i++)
cout<<a[x[i]].nr<<". "<<a[x[i]].tara<<endl;
nr++;
cout<<endl;}
int verif(int i)
{if(strcmp(a[x[i]].tara,a[x[i-1]].tara)==0)
return 0;
for(int j=1;j<i;j++)
if(a[x[i]].nr==a[x[j]].nr)
return 0;
return 1;
}
void back(int i)
{int j;
for(j=1;j<=n;j++)
{x[i]=j;
if(verif(i))
if(i==n)
afisare(n);
else back(i+1);
}
}
int main()
{int i,j;
cin>>n;
for(i=1;i<=n;i++)
{a[i].nr=i;
cin>>a[i].tara;
}
back(1);
cout<<nr<<" solutii";
}
#include<iostream>
using namespace std;
int n,x[10],nr=0;
struct concurent{
int nr;
char tara[100];
}a[100];
int afisare(int n)
{for(int i=1;i<=n;i++)
cout<<a[x[i]].nr<<". "<<a[x[i]].tara<<endl;
nr++;
cout<<endl;}
int verif(int i)
{if(strcmp(a[x[i]].tara,a[x[i-1]].tara)==0)
return 0;
for(int j=1;j<i;j++)
if(a[x[i]].nr==a[x[j]].nr)
return 0;
return 1;
}
void back(int i)
{int j;
for(j=1;j<=n;j++)
{x[i]=j;
if(verif(i))
if(i==n)
afisare(n);
else back(i+1);
}
}
int main()
{int i,j;
cin>>n;
for(i=1;i<=n;i++)
{a[i].nr=i;
cin>>a[i].tara;
}
back(1);
cout<<nr<<" solutii";
}
Problema 4
n persoane stau pe scaune numerotate de la 1 la n. Oricare doi vecini se ceartă. Să se afişeze toate posibilităţile de a-i reaşeza pe scaune astfel încât să nu fie 2 foşti vecini alăturaţi.
#include<iostream>
using namespace std;
int nr=0,n,x[100],k;
char a[10]=" 01";
void afisare(int n)
{int i;
nr++;
for(i=1;i<=n;i++)
cout<<x[i]<<" ";
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(x[j]==x[i])
return 0;
if(i>1 && abs(x[i]-x[i-1])<=1)
return 0;
return 1;}
void back(int i)
{int j;
for(j=1;j<=n;j++)
{x[i]=j;
if(verif(i))
if(i==n)
afisare(n);
else back(i+1);
}
}
int main()
{int i;
cin>>n;
for(i=1;i<=n;i++)
x[i]=i;
back(1);
cout<<endl<<nr;
}
#include<iostream>
using namespace std;
int nr=0,n,x[100],k;
char a[10]=" 01";
void afisare(int n)
{int i;
nr++;
for(i=1;i<=n;i++)
cout<<x[i]<<" ";
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(x[j]==x[i])
return 0;
if(i>1 && abs(x[i]-x[i-1])<=1)
return 0;
return 1;}
void back(int i)
{int j;
for(j=1;j<=n;j++)
{x[i]=j;
if(verif(i))
if(i==n)
afisare(n);
else back(i+1);
}
}
int main()
{int i;
cin>>n;
for(i=1;i<=n;i++)
x[i]=i;
back(1);
cout<<endl<<nr;
}
Problema 3
Sa se scrie un algoritm BackTracking care genereaza toate sirurile de 5 cifre 0 si 1 astfel incat sa nu existe mai mult de doua cifre de 0 alaturate.
#include<iostream>
using namespace std;
int nr=0,n,x[10],k;
char a[10]=" 01";
void afisare()
{int i;
nr++;
for(i=1;i<=5;i++)
cout<<a[x[i]]<<" ";
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(i>1 && a[x[i]]=='0' && a[x[i-1]]=='0')
return 0;
return 1;}
void back(int i)
{int j;
for(j=1;j<=2;j++)
{x[i]=j;
if(verif(i))
if(i==5)
afisare();
else back(i+1);
}
}
int main()
{back(1);
cout<<endl<<nr;
}
#include<iostream>
using namespace std;
int nr=0,n,x[10],k;
char a[10]=" 01";
void afisare()
{int i;
nr++;
for(i=1;i<=5;i++)
cout<<a[x[i]]<<" ";
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(i>1 && a[x[i]]=='0' && a[x[i-1]]=='0')
return 0;
return 1;}
void back(int i)
{int j;
for(j=1;j<=2;j++)
{x[i]=j;
if(verif(i))
if(i==5)
afisare();
else back(i+1);
}
}
int main()
{back(1);
cout<<endl<<nr;
}
Problema 2
n copii sunt pregatiti pentru ora de sport. Se cunoaste inaltimea fiecaruia. Trebuie alesi k copii insirati pe un rand astfel incat diferenta dintre oricare 2 elevi sa nu fie mai mare de 10 cm.
#include<iostream>
using namespace std;
int nr=0,n,x[10],k;
int a[100];
void afisare(int k)
{int i;
nr++;
for(i=1;i<=k;i++)
cout<<a[x[i]]<<" ";
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(x[j]==x[i])
return 0;
if(i>1 && abs(a[x[i]]-a[x[i-1]])>10)
return 0;
return 1;}
void back(int i)
{int j;
for(j=1;j<=n;j++)
{x[i]=j;
if(verif(i))
if(i==k)
afisare(k);
else back(i+1);
}
}
int main()
{cout<<"n=";cin>>n;
cout<<"k=";cin>>k;
for(int i=1; i<=n;i++)
cin>>a[i];
back(1);
cout<<endl<<nr;
}
#include<iostream>
using namespace std;
int nr=0,n,x[10],k;
int a[100];
void afisare(int k)
{int i;
nr++;
for(i=1;i<=k;i++)
cout<<a[x[i]]<<" ";
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(x[j]==x[i])
return 0;
if(i>1 && abs(a[x[i]]-a[x[i-1]])>10)
return 0;
return 1;}
void back(int i)
{int j;
for(j=1;j<=n;j++)
{x[i]=j;
if(verif(i))
if(i==k)
afisare(k);
else back(i+1);
}
}
int main()
{cout<<"n=";cin>>n;
cout<<"k=";cin>>k;
for(int i=1; i<=n;i++)
cin>>a[i];
back(1);
cout<<endl<<nr;
}
Problema 1
Sa se genereze cuvintele de k litere care incep cu o vocala si se termina cu o consoana.
#include<iostream>
using namespace std;
int nr=0,n,x[10],k;
char a[10]=" abcdefgh";
void afisare(int k)
{int i;
nr++;
for(i=1;i<=k;i++)
cout<<a[x[i]];
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(x[j]==x[i])
return 0;
if(i==1 && strchr("aeiou",a[x[i]])==0)
return 0;
if(i==k && strchr("aeiou",a[x[i]])!=0)
return 0;
return 1;}
void back(int i)
{int j;
for(j=1;j<=8;j++)
{x[i]=j;
if(verif(i))
if(i==k)
afisare(k);
else back(i+1);
}
}
int main()
{cin>>k;
back(1);
cout<<endl<<nr;
}
#include<iostream>
using namespace std;
int nr=0,n,x[10],k;
char a[10]=" abcdefgh";
void afisare(int k)
{int i;
nr++;
for(i=1;i<=k;i++)
cout<<a[x[i]];
cout<<endl;
}
int verif(int i)
{int j;
for(j=1;j<i;j++)
if(x[j]==x[i])
return 0;
if(i==1 && strchr("aeiou",a[x[i]])==0)
return 0;
if(i==k && strchr("aeiou",a[x[i]])!=0)
return 0;
return 1;}
void back(int i)
{int j;
for(j=1;j<=8;j++)
{x[i]=j;
if(verif(i))
if(i==k)
afisare(k);
else back(i+1);
}
}
int main()
{cin>>k;
back(1);
cout<<endl<<nr;
}
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